21x^2+41xy-40y^2=

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Solution for 21x^2+41xy-40y^2= equation:


Simplifying
21x2 + 41xy + -40y2 = 0

Reorder the terms:
41xy + 21x2 + -40y2 = 0

Solving
41xy + 21x2 + -40y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(7x + -5y)(3x + 8y) = 0

Subproblem 1

Set the factor '(7x + -5y)' equal to zero and attempt to solve: Simplifying 7x + -5y = 0 Solving 7x + -5y = 0 Move all terms containing x to the left, all other terms to the right. Add '5y' to each side of the equation. 7x + -5y + 5y = 0 + 5y Combine like terms: -5y + 5y = 0 7x + 0 = 0 + 5y 7x = 0 + 5y Remove the zero: 7x = 5y Divide each side by '7'. x = 0.7142857143y Simplifying x = 0.7142857143y

Subproblem 2

Set the factor '(3x + 8y)' equal to zero and attempt to solve: Simplifying 3x + 8y = 0 Solving 3x + 8y = 0 Move all terms containing x to the left, all other terms to the right. Add '-8y' to each side of the equation. 3x + 8y + -8y = 0 + -8y Combine like terms: 8y + -8y = 0 3x + 0 = 0 + -8y 3x = 0 + -8y Remove the zero: 3x = -8y Divide each side by '3'. x = -2.666666667y Simplifying x = -2.666666667y

Solution

x = {0.7142857143y, -2.666666667y}

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